5x^2-20x+7.2=0

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Solution for 5x^2-20x+7.2=0 equation:



5x^2-20x+7.2=0
a = 5; b = -20; c = +7.2;
Δ = b2-4ac
Δ = -202-4·5·7.2
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-16}{2*5}=\frac{4}{10} =2/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+16}{2*5}=\frac{36}{10} =3+3/5 $

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